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1/√4%9x²Dx

解:∫(1-x)/√(4-9x²)dx=∫1/√(4-9x²)-∫x/√(4-9x²)dx=1/3∫1/√[1-(3x/2)²]d(3x/2)+1/18∫1/√(4-9x²)d(4-9x²)=1/3·arcsinx+1/18·2/3·(4-9x²)^(3/2)+C=1/3·arcsinx+1/27·(4-9x²)^(3/2)+C

∫ (1 - x)/√(4 - 9x²) dx Let x = (2/3)sinz,dx = (2/3)cosz dz √(4 - 9x²) = √(4 - 4sin²z) = 2cosz => ∫ (1 - (2/3)sinz)/(2cosz) * (2/3)cosz dz = (1/3)∫ (1 - (2/3)sinz) dz = (1/3)∫ dz - (2/9)∫ sinz dz = (1/3)z - (2/9)...

2(3x-1)=3(3x+1)或者2(3X-1)=-3(3x+1) 6x-2=9x+3或者6x-2=-9x-3 x=-5\9或者x=-1/15

已知x=二分之根号2+1求代数式4x4次方加4x3次方减9x平方减2x加一的值 4x4次方加4x3次方减9x平方减2x加一 =4x4次方+4x3次方+x²-10x²-2x+1 =x²(2x+1)²-10x²-2x+1 =[(√2+1)/2]²[2*(√2+1)/2+1]²-10[(√2+1)/2]...

y=(5x²+9x+4)÷(x²-1)=(5x+4)(x+1)/[(x+1)(x-1) =(5x+4)/(x-1)=(5x-5+9)/(x-1) =5+9/(x-1) y≠5

您好: 9x²+6x+1=4 9x²+6x-3=0 3x²+2x-1=0 (3x-1)(x+1)=0 x1=1/3 x2=-1 (x-3)²=4(2x+1)² 4(2x+1)² -(x-3)²=0 (4x+2+x-3)(4x+2-x+3)=0 (5x-1)(3x+5)=0 x1=1/5 x2=-5/3 (x+1)²-4(x+1)+4=5 (x+1...

(1)双曲线方程是 9x^2-16y^2=144 么?? 化为 x^2/16-y^2/9=1 ,因此 a^2=16 ,b^2=9 ,c^2=a^2+b^2=25 , 所以 a=4 ,b=3 ,c=5 , 则实半轴长为 4 ,虚半轴长为 3 ,焦点坐标为(-5,0)、(5,0), 离心率为 e=c/a=5/4 ,渐近线方程为 y=±...

9X²+12XY+4Y²-(4X²-12XY+9Y²) =9X²+12XY+4Y²-4X²+12XY-9Y² =5X²+24XY-5Y² =(X+5Y)(5X-Y) 其中x=4/5,y=-1/5 原式=(4/5-5×1/5)(5×4/5+1/5) =-1/5×21/5 =-21/25

y=1/3x²-3x+2 =1/3(x²-9x)+2 =1/3(x-9/2)²+2-27/4 =1/3(x-9/2)²-19/4 当x=9/2的时候,y有最小值=-19/4 x≤9/2的时候,单调递减 x>9/2的时候,单调递增

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