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1,%2,2,3四个数怎么算24点?

不详

(-1)^2=1 (-2)^2=4 1×4×2×3=24

1: (1 + 2 + 3) × 4 2: ((1 + 2) + 3) × 4 3: (1 + (2 + 3)) × 4 4: 1 × 2 × 3 × 4 5: (1 × 2) × 3 × 4 6: (1 × 2 × 3) × 4 7: ((1 × 2) × 3) × 4 8: (1 × (2 × 3)) × 4 9: 1 × (2 × 3) × 4 10: 1 × (2 × 3 × 4) 11: 1 × ((2 × 3) × 4) 12: 1 × ...

2³×[1-﹙-2﹚]=24

解答1: {1-(-2)} *(2)的三次方=3*8=24 解答2: { 3-(-2)}的平方-1=25-1=24

3*4*(5-1-2)=24 4*5+2+3-1+24 (5-2+3)*4*1=24 (5+3)*(4+1-2)=24 3*5+2*4=1=24 2*5*(3-1)+4=24

(13-2+1)*2=24

57

呵呵,很简单的! 1、常规运算: -1*(-2*3*4) (-2*3*4)/(-1) (2+3-(-1))*4 (2*3)/(-(-1/4)) 2、特殊运算: ((-(-1))'+2'+3'+4')! 导数:自然数的导数为1 阶乘:0!=1!=1 求余:符号为:mod,即求余运算得到的余数

3×[10+4+(-6)]=24 3×(10-4)-(-6)=24 10-4-3×(-6)=24 4-(-6)×10÷3=24 望采纳谢谢

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