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用洛比达法则求极限limx→0[x(E^x+1)%2(E^x%1)]...

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=lim {e^[(㏑(1+x) )/x]/e}^1/x =lim {{e^[1/(1+x)]}/e}^1/x 这步不等吧~~~是这里错了 根据罗比达法则这个应该等于x根号e^[1/(1+x)]}的微分/x根号e的微分

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lim(x->e) (lnx-1)/(x-e) (0/0) = lim(x->e) (1/x)/1 =1/e or expands lnx about e lnx = lne +(x-e)/e + (x-e)^2/e^2+... = 1+(x-e)/e + (x-e)^2/e^2+... (lnx-1)/(x-e) = [ 1+(x-e)/e + (x-e)^2/e^2+... - 1] /(x-e) = ((x-e)/e + (x-e)^2/e^2...

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