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已知函数Fx=sinx四次幂+2倍根号三sinxCosx%Cosx的...

fx=2sin²x+2√3sinxcosx+1 =1-cos2x+√3sin2x+1 =2sin(2x-π/6)+2 ∴周期是π,值域是:f(x)∈[0,4]

解答如图

fx=2根号3sinxcosx-cos2x =2(根号3/2sin2x-1/2cos2x) =2sin(2x-派/6) 增区间: 2k派-派/3

f(x)=√3sinxcosx+cos²x =(√3/2)·2sinxcosx+½(2cos²x-1)+½ =(√3/2)sin2x+½cos2x+½ =sin(2x+π/6) +½ 最小正周期T=2π/2=π

你好: f(x)=√3sinxcosx–cos²x+1/2 =√3sinxcosx–1/2(1-cos²x)+1/2 =√3/2sin2x+1/2cos²x-1/2+1/2 =sin(2x+π/6) T=2π/2=π 希望能帮助你:

f(x)=sin^2x+√3sinxcosx+2cos^2x =cos^2x+√3/2*2sinxcosx+1 =1/2cos2x+√3/2sin2x+3/2 =sinx(2x+π/6)+3/2 T=2π/2=π 2x+π/6在[2kπ-π/2,2kπ+π/2]上单调递增 x在[kπ-5π/12,kπ+π/6]上单调递增 2)y=sin2x的图像经X轴向左平移π/12个单位得到y=sinx(2x+...

求采纳,

fx=1+根号2cos(2x-派/4)/sin(x+派/2) =1+(cos2x+sin2x)/cosx =1+cosx+sin^x/cosx+2sinx =1+cosx+1/cosx-cosx+2sinx =1+1/cosx+2sinx

你好:f(x)=√3sinxcosx–cos²x+1/2 =√3sinxcosx–1/2(1-cos²x)+1/2 =√3/2sin2x+1/2cos²x-1/2+1/2 =sin(2x+π/6)T=2π/2=π f(x)=√3sinxcosx-cos²x+1/2=(√3/2)(2sinxcosx)-(1/2)(2cos²x-1) 二倍角公式:2sinxcosx=sin(2x),...

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