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如何用Python循环语句制作n的阶乘

def jieshen(n): sum = 1 while sum

from functools import reducefrom operator import muldef jiecheng(n): return reduce(mul, range(1, n+1)) if __name__ == '__main__': for i in range(3, 10): print('{}! = {}'.format(i, jiecheng(i)))wenjie@digi007:~/study/zhidao$ pyt...

def fact(n):if n==0:return 1else:return n*fact(n-1)n=int(input())print(fact(n))

可以用循环loop或递归来(recursion)来解决类似问题 应用loop: def factorial_loop(n): res = 1 for i in range((1,n+1): res *= i return res print factorial(15) 2. recursion def factorial_recursion(n): if n >> 1307674368000 此外还可...

def jiezheng(n): if n==1 or n==0: return 1 return n*jiezheng(n-1)递归调用函数jiezheng算阶乘 jiezheng(5) 返回120

阶乘有一个经典的递归调用算法。以下是示例代码。 def jiecheng(n): if n==1 or n==0: return 1 return n*jiecheng(n-1)print('5的阶乘为%s'%jiecheng(5))

def factorial(n): if n == 1: return 1 else: return n * factorial(n - 1)input_num = input()try: with open('jc.txt', 'w') as file: file.write(str(factorial(int(input_num))))except IOError as e: print('error', e)

def getDigits(data): digits = [] while data / 10: digits.append(data % 10) data /= 10 digits.append(data) print digits return digitsdef sumNfabric(data): digits = getDigits(data) digits.sort() print digits sumOfDigitsFabric = 0...

#!/usr/bin/env python3.6import refrom math import factorial as facdef get_k(n, a): nn = fac(n) for k in range(1, n): ak = a**k if nn % ak == 0 and nn % (ak * k) != 0: return kdef main(): inp = input('Enter two integers: ') n, a...

python不鼓励递归,请看这个函数的递归版(def sn_recursion)和非递归版(def sn)的代码对比:

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