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求1/(4+9x^2)的不定积分 求1/(4x^2+4x+5)的不定积分

详细解答如下,点击放大:

x=roots([3 4 7 2 9 12]) 或 x=double(solve('3*x^5+4*x^4+7*x^3+2*x^2+9*x+12')) 结果: x = -0.9583 0.6737 + 1.0159i -0.8612 - 1.4377i -0.8612 + 1.4377i 0.6737 - 1.0159i

1/1x2+1/2x3+1/3x4+1/4x5+……1/8x9+1/9x10 =1-1/2+1/2-1/3+1/3-1/4+....+1/8-1/9+1/9-1/10 =1-1/10 =9/10

1.9x-9/4-4x =9(x-1)/4(1-x) =-9/4 2.x^2-1/x^2+x-2 =(x+1)(x-1)/(x-1)(x+2) =(x+1)/(x+2) 3.x^2-4x+4/2x-4 =(x-2)²/2(x-2) =(x-2)/2 4.3x^2-9x-12/x^2+2x+1 =3(x-4)(x+1)/(x+1)² =3(x-4)/(x+1) 5.x^2-7x+12/-x^2+9x-20 =(x-3)(x-4)/-...

1x2/1+2x3/1+3x4/1+4x5/1+5x6/1+6x7/1+7x8/1+8x9/1+9x10/1 =1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90 =(1-1/2)+(1/2-1/3)+……+(1/8-1/9)+(1/9-1/10) =1-1/10 =9/10

①4x-4/9x=2/5 32/9x=2/5 x=2/5÷32/9 x=9/80 ②1-0.5x=1/2 0.5x=1-1/2 0.5x=1/2 x=1/2÷0.5 x=1

(3x+2)(3x-2)-5x(x-1)-(2x-1)^2 =9x^2-4-5x^2+5x-4x^2+4x-1 =9x-5 将x代入得 -1/3*9-5 =-3-5 =-8

因为an=n*(n-1)/n+1 所以每个数可以看成2/3+(1+2/4)+(2+2/5)+(3+2/6)...+(8+2/11)= 1+2+3...+8+2/3+2/4+2/5...+2/11=36+2*(1/3+1/4+1/5+...1/11) 因为后面的那个是一个发散数列,好像没有求和公式,所以只能同分计算,当然可以把简单...

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1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8+1/8x9+1/9x10 =1-1/2+1/2-1/3+1/3-....-1/9+1/9-1/10 =1-1/10 =9/10

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