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计算反常积分从负无穷到正无穷(4+9x²)分之1Dx

∫ (1 - x)/√(4 - 9x²) dx Let x = (2/3)sinz,dx = (2/3)cosz dz √(4 - 9x²) = √(4 - 4sin²z) = 2cosz => ∫ (1 - (2/3)sinz)/(2cosz) * (2/3)cosz dz = (1/3)∫ (1 - (2/3)sinz) dz = (1/3)∫ dz - (2/9)∫ sinz dz = (1/3)z - (2/9)...

(- 1/2 x²y )^3 * ( ﹣3xy²)² =(-1/8 x^6 y^3)*(9x^2 y^4) =-9/8x^8 y^7 (4+3x) (-4+3x)-(3x-2)² =-(4+3x)(4-3x)-(3x-2)^2 =-(16-9x^2)-(9x^2-12x+4) =-16+9x^2-9x^2+12x-4 =12x-20 =4(3x-5) (27a的三次方x² - 9...

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