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高等数学,不定积分.题目(∫(9x+4)/(3x^2%2x%1...

∫ 1/(4+9x²) dx = (1/4) ∫ dx/[1+(3x/2)²] = (1/4)(2/3) ∫ d(3x/2)/[1+(3x/2)²] = (1/6)arctan(3x/2) + C

详细解答如下,点击放大:

这个也太多了吧?这些都是很简单的东西,只要代公式化简就行啊

=(x-1)*(x-4)*(x+3)*(x+6)+108 =(x-1)(x+3)*(x-4)(x+6)+108 =(x²+2x-3)*(x²+2x-24)+108 =(x²+2x)² -27(x²+2x)+72+108 =(x²+2x)² -27(x²+2x)+180 =(x²+2x-12)(x...

见图

(x^2-5x+4)(x^2+9x+18)+108 =x^4+4x^3-23x^2-54x+180 =x^3(x-3)+7x^2(x-3)-2x(x-3)-60(x-3) =(x-3)(x^3+7x^2-2x-60) =(x-3)[x^2(x+5)+2x(x+5)-12(x+5)] =(x-3)(x+5)(x^2+2x-12)

解: 增广矩阵 = 2 7 3 1 6 3 5 2 2 4 9 4 1 7 2 r3-3r2,r2-r1 2 7 3 1 6 1 -2 -1 1 -2 0 -11 -5 1 -10 r1-2r2 0 11 5 -1 10 1 -2 -1 1 -2 0 -11 -5 1 -10 r3+r1,r1*(1/11),r2+2r1 0 1 5/11 -1/11 10/11 1 0 -1/11 9/11 -2/11 0 0 0 0 0 交换行 (...

x 后面的是下标,不是次方,否则不是线性方程组。 增广矩阵 (A, b) = [1 1 3 -1 1] [3 -1 -3 4 4] [1 5 9 -8 0] 初等行变换为 [1 1 3 -1 1] [0 -4 -15 7 1] [0 4 6 -7 -1] 初等行变换为 [1 1 3 -1 1] [0 4 15 -7 -1] [0 0 -9 0 0] 初等行变换为...

数学之美团员为您解答,答案在图片上 希望得到采纳,谢谢≧◔◡◔≦

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