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对sin3x/sin5x求极限(x→0)

lim (sin3x-sin5x)/x x→0 =lim 2cos4xsin(-x)/x x→0 =lim -2x·cos4x/x x→0 =lim -2cos4x x→0 =-2cos0 =-2·1 =-2

lim(x→0)( sin3x)/(5x) =lim(x→0)(3cos3x)/5 =3/5 =0.6 朋友,请采纳正确答案,你们只提问,不采纳正确答案,回答都没有劲!!! 朋友,请【采纳答案】,您的采纳是我答题的动力,如果没有明白,请追问。谢谢。

和这个思路一样!

lim(x->0) (sin5x - sin3x)/sinx =lim(x->0) (5x - 3x)/x =2

设f(x)=sinx-2sin3x+sin5x是x的k阶无穷小量,则limx→0f(x)xk=c≠0,∴c=limx→0sinx?2sin3x+sin5xxk=limx→0cosx?6cos3x+5cos5xkxk?1=limx→0sinx+18sin3x?25sin5xk(k?1)xk?2=limx→0cosx+54cos3x?125cos5xk(k?1)(k?2)xk?3由于此时分子的极限为1+5...

 limsin3x/tan5x =lim3cos3x/[5(sec5x)^2] =(3/5)limcos3x(cos5x)^2 =(3/5)cos3π(cos5π)^2 =-3/5 limtanx/x=limx/x=1

x→0 lim sin3x/tan5x =lim sin3x*cos5x / sin5x =lim sin3x/3x * 3x/5x * 5x/sin5x * cos5x =lim sin3x/3x * lim 3x/5x * lim 5x/sin5x * lim cos5x 根据重要的极限:lim(x→0) sinx/x=1 =lim 3/5 * lim cos5x =3/5 * 1 =3/5 有不懂欢迎追问

用罗必答法则 得1

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