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(%1/2)^2015+(%1/2)^2016

2^2016-2^2015 =2x2^2015-2^2015 =(2-1)2^2015 =2^2015

a^2017=a^2016xa,∴(-2)^2017=(-2)^2016x(-2)

=2^2017-1

=(-2)^1016+(-2)^2015 =2^2016-2^2015 =2*2^2015-2^2015 =(2-1)*2^2015 =2^2015

(1+√2)^2015 x (1-√2)^2016 = ( (1+√2)(1-√2) )^2015 x (1-√2) =( -1)^2015x (1-√2) =√2 - 1

e^(-1/2)=1/√e≈1/√2.71828≈1/1.64872≈0.606531 (2015/2016)^1005≈0.607359 偏偏(2015/2016)^1005>e^(-1/2)

0

2015²+2015+1=2015×(2015+1)+1 =2015×2016+1 所以(2015²+2015+1)/2016=(2015×2016+1)/2016 =2015+(1/2016) 所以不能被2016整除 望采纳

1/2016+2/2016+3/2016......2015/2016 =(1+2+3......2015)/2016 =2015/2×2016/2016 =1007.5

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