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(%1/2)^2015+(%1/2)^2016

a^2017=a^2016xa,∴(-2)^2017=(-2)^2016x(-2)

(-1.25)^2016×1.6^2015×(1/2)^2015 =(1.25)^2016×1.6^2015×(1/2)^2015 =(1.25×1.6×1/2)^2015×1.25 =1^2015×1.25 =1.25

=2^2017-1

=(-2)^1016+(-2)^2015 =2^2016-2^2015 =2*2^2015-2^2015 =(2-1)*2^2015 =2^2015

(1+√2)^2015 x (1-√2)^2016 = ( (1+√2)(1-√2) )^2015 x (1-√2) =( -1)^2015x (1-√2) =√2 - 1

1+2+4+......+2的2015次方+2的2016次方,即求等比数列的和Sn=a1(1-qn)/(1-q)其中公比q=2,n=2017,代入得sn=2的2017次方-1

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1/2016+2/2016+3/2016......2015/2016 =(1+2+3......2015)/2016 =2015/2×2016/2016 =1007.5

你发题目图片吧,你打的这个应该和原题不同

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