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(%1/2)^2015+(%1/2)^2016

原式=(根号3+1)^2015*((根号3+1)^2-2*(根号3+1)-2)+2018 =(根号3+1)^2015*(3+2*根号3+1-2*根号3-2-2)+2018 =(根号3+1)^2015*0+2018 =2018

完整题目是不是 已知a=1/2015+2O14,b=1/2015+2015,C=1/2015+2016,则代数式2(a^2+b^2+C^2-ab-bc-ac)等于多少? 解: 2(a^2+b^2+C^2-ab-bc-ac)=a^2-2ab+b^2+a^2-2ac+c^2+b^2-2bc+c^2=(a-b)^2+(a-c)^2+(c-b)^2=1^2+2^2+1^2=6

你发题目图片吧,你打的这个应该和原题不同

你好 a^2+b^2+c^2-ab-ac-bc =1/2×(a^2-2ab+b^2+b^2-2bc+c^2+c^2-2ac+a^2) =1/2×[(a-b)²+(b-c)²+(a-c)²] =1/2×(1+1+4) =3

设a2015 √(2014x2015x2016x2017+1)-2015² =√[(a-1)a(a+1)(a+2)+1]-a² =√[(a²+a)(a²+a-2)+1]-a² =√[(a²+a)²-2(a²+a)+1]-a² =√(a²+a-1)²-a² =a²+a-1-a² =a-1 =2015-1 =2014

1/2016+2/2016+3/2016......2015/2016 =(1+2+3......2015)/2016 =2015/2×2016/2016 =1007.5

(-1)+(+2)+(-3)+(+4)…+(-2015)+(+2016) =(2-1)+(4-3)+……+(2016-2015) =1+1+……+1 =2016÷2 =1008

(1+1/2)×(1+1/3)×(1+1/4)×...×(1+1/2015)×(1+1/2016) =3/2×4/3×5/4×……×2016/2015×2017/2016 =2017/(2×2015) =2017/4030。

(-2015又5/6)+(-2016又2/3)+4032+(-1又1/2) =【(-2015)+(-2016)+4032】+【(-5/6)+(-2/3)+(-1/2)】 =【(-4031)+4032】+【(-1/2)+(-1/3)+(-2/3)+(-1/2)】 =1+(-2) =-1

(1-2)×(2-3)×……×(2015-2016)×(2016-2017) =(-1)×(-1)×……×(-1)×(-1)(共2016个) =1

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